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1202120443141 = 3138778078811
BaseRepresentation
bin10001011111100011111…
…101100100010100000101
311020220212211200210010121
4101133203331210110011
5124143420313140031
62320125125021541
7152564444113012
oct21374375442405
94226784623117
101202120443141
114238a8718442
12174b8b8548b1
13894899b28a7
144227bdb6709
152140ae40011
hex117e3f64505

1202120443141 has 4 divisors (see below), whose sum is σ = 1240898521984. Its totient is φ = 1163342364300.

The previous prime is 1202120443109. The next prime is 1202120443151. The reversal of 1202120443141 is 1413440212021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1202120443141 - 25 = 1202120443109 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1202120443151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19389039375 + ... + 19389039436.

It is an arithmetic number, because the mean of its divisors is an integer number (310224630496).

Almost surely, 21202120443141 is an apocalyptic number.

It is an amenable number.

1202120443141 is a deficient number, since it is larger than the sum of its proper divisors (38778078843).

1202120443141 is an equidigital number, since it uses as much as digits as its factorization.

1202120443141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38778078842.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 1202120443141 its reverse (1413440212021), we get a palindrome (2615560655162).

The spelling of 1202120443141 in words is "one trillion, two hundred two billion, one hundred twenty million, four hundred forty-three thousand, one hundred forty-one".

Divisors: 1 31 38778078811 1202120443141