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12021212013 = 341531844027
BaseRepresentation
bin10110011001000010…
…10010001101101101
31011000210000211202120
423030201102031231
5144104412241023
65304504143153
7603616421226
oct131441221555
934023024676
1012021212013
11510972a568
1223b5a67ab9
131197680805
1482078024d
154a55608e3
hex2cc85236d

12021212013 has 16 divisors (see below), whose sum is σ = 16729022016. Its totient is φ = 7671148160.

The previous prime is 12021212009. The next prime is 12021212029. The reversal of 12021212013 is 31021212021.

It is a cyclic number.

It is not a de Polignac number, because 12021212013 - 22 = 12021212009 is a prime.

It is a super-4 number, since 4×120212120134 (a number of 41 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 12021211983 and 12021212001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12021212003) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 915495 + ... + 928532.

It is an arithmetic number, because the mean of its divisors is an integer number (1045563876).

Almost surely, 212021212013 is an apocalyptic number.

It is an amenable number.

12021212013 is a deficient number, since it is larger than the sum of its proper divisors (4707810003).

12021212013 is a wasteful number, since it uses less digits than its factorization.

12021212013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1844124.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 12021212013 its reverse (31021212021), we get a palindrome (43042424034).

The spelling of 12021212013 in words is "twelve billion, twenty-one million, two hundred twelve thousand, thirteen".

Divisors: 1 3 41 53 123 159 2173 6519 1844027 5532081 75605107 97733431 226815321 293200293 4007070671 12021212013