Base | Representation |
---|---|
bin | 1010111011101111001101… |
… | …0010011111000100100011 |
3 | 1120120020100001100002020010 |
4 | 2232323303102133010203 |
5 | 3033424311423003210 |
6 | 41322315514420003 |
7 | 2350342334520351 |
oct | 256736322370443 |
9 | 46506301302203 |
10 | 12021400203555 |
11 | 391527a021546 |
12 | 14219b2731603 |
13 | 6927c81b7822 |
14 | 2d7ba5c2a7d1 |
15 | 15ca86a71920 |
hex | aeef349f123 |
12021400203555 has 32 divisors (see below), whose sum is σ = 19253180104704. Its totient is φ = 6405101225856.
The previous prime is 12021400203503. The next prime is 12021400203559. The reversal of 12021400203555 is 55530200412021.
It is not a de Polignac number, because 12021400203555 - 228 = 12021131768099 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12021400203559) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 242034654 + ... + 242084316.
It is an arithmetic number, because the mean of its divisors is an integer number (601661878272).
Almost surely, 212021400203555 is an apocalyptic number.
12021400203555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12021400203555 is a deficient number, since it is larger than the sum of its proper divisors (7231779901149).
12021400203555 is a wasteful number, since it uses less digits than its factorization.
12021400203555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 65235.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 12021400203555 its reverse (55530200412021), we get a palindrome (67551600615576).
The spelling of 12021400203555 in words is "twelve trillion, twenty-one billion, four hundred million, two hundred three thousand, five hundred fifty-five".
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