120214113132 has 12 divisors (see below), whose sum is σ = 280499597336. Its totient is φ = 40071371040.

The previous prime is 120214113113. The next prime is 120214113143. The reversal of 120214113132 is 231311412021.

It is a tau number, because it is divible by the number of its divisors (12).

It is a super-2 number, since 2×120214113132² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120214113099 and 120214113108.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5008921369 + ... + 5008921392.

Almost surely, 2^120214113132 is an apocalyptic number.

120214113132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

120214113132 is an abundant number, since it is smaller than the sum of its proper divisors (160285484204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120214113132 is a wasteful number, since it uses less digits than its factorization.

120214113132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10017842768 (or 10017842766 counting only the distinct ones).

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 120214113132 its reverse (231311412021), we get a palindrome (351525525153).

The spelling of 120214113132 in words is "one hundred twenty billion, two hundred fourteen million, one hundred thirteen thousand, one hundred thirty-two".