Base | Representation |
---|---|
bin | 1010111011110000001001… |
… | …1001010100000100100011 |
3 | 1120120020222201020120210012 |
4 | 2232330002121110010203 |
5 | 3033430321313323442 |
6 | 41322401010555135 |
7 | 2350351533013355 |
oct | 256740231240443 |
9 | 46506881216705 |
10 | 12021653651747 |
11 | 391539a09a963 |
12 | 1421a63598aab |
13 | 69283886687c |
14 | 2d7bcb7630d5 |
15 | 15ca9de37582 |
hex | aef02654123 |
12021653651747 has 2 divisors, whose sum is σ = 12021653651748. Its totient is φ = 12021653651746.
The previous prime is 12021653651629. The next prime is 12021653651767. The reversal of 12021653651747 is 74715635612021.
It is a strong prime.
It is an emirp because it is prime and its reverse (74715635612021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12021653651747 - 216 = 12021653586211 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12021653651695 and 12021653651704.
It is not a weakly prime, because it can be changed into another prime (12021653651767) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6010826825873 + 6010826825874.
It is an arithmetic number, because the mean of its divisors is an integer number (6010826825874).
Almost surely, 212021653651747 is an apocalyptic number.
12021653651747 is a deficient number, since it is larger than the sum of its proper divisors (1).
12021653651747 is an equidigital number, since it uses as much as digits as its factorization.
12021653651747 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2116800, while the sum is 50.
The spelling of 12021653651747 in words is "twelve trillion, twenty-one billion, six hundred fifty-three million, six hundred fifty-one thousand, seven hundred forty-seven".
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