Base | Representation |
---|---|
bin | 1010111011110001100011… |
… | …1101110010011101000011 |
3 | 1120120021222002202112011212 |
4 | 2232330120331302131003 |
5 | 3033432110232442011 |
6 | 41322502335000335 |
7 | 2350364111406452 |
oct | 256743075623503 |
9 | 46507862675155 |
10 | 12022032312131 |
11 | 3915573910026 |
12 | 1421b4a3690ab |
13 | 69289914607a |
14 | 2d7c25b70b99 |
15 | 15cac22d308b |
hex | aef18f72743 |
12022032312131 has 2 divisors, whose sum is σ = 12022032312132. Its totient is φ = 12022032312130.
The previous prime is 12022032311969. The next prime is 12022032312197. The reversal of 12022032312131 is 13121323022021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12022032312131 - 242 = 7623985801027 is a prime.
It is a super-2 number, since 2×120220323121312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12022032312097 and 12022032312106.
It is not a weakly prime, because it can be changed into another prime (12022032312931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011016156065 + 6011016156066.
It is an arithmetic number, because the mean of its divisors is an integer number (6011016156066).
Almost surely, 212022032312131 is an apocalyptic number.
12022032312131 is a deficient number, since it is larger than the sum of its proper divisors (1).
12022032312131 is an equidigital number, since it uses as much as digits as its factorization.
12022032312131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 12022032312131 its reverse (13121323022021), we get a palindrome (25143355334152).
The spelling of 12022032312131 in words is "twelve trillion, twenty-two billion, thirty-two million, three hundred twelve thousand, one hundred thirty-one".
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