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1202210020201 = 2129875644523
BaseRepresentation
bin10001011111101001010…
…011010001101101101001
311020221010002020202202111
4101133221103101231221
5124144111231121301
62320142045002321
7152566612364431
oct21375123215551
94227102222674
101202210020201
1142394423aa73
12174bb58533a1
13894a2417178
1442289c532c1
1521413c36551
hex117e94d1b69

1202210020201 has 4 divisors (see below), whose sum is σ = 1202215877712. Its totient is φ = 1202204162692.

The previous prime is 1202210020181. The next prime is 1202210020241. The reversal of 1202210020201 is 1020200122021.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1202210020201 - 25 = 1202210020169 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1202210020241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2609275 + ... + 3035248.

It is an arithmetic number, because the mean of its divisors is an integer number (300553969428).

Almost surely, 21202210020201 is an apocalyptic number.

It is an amenable number.

1202210020201 is a deficient number, since it is larger than the sum of its proper divisors (5857511).

1202210020201 is an equidigital number, since it uses as much as digits as its factorization.

1202210020201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5857510.

The product of its (nonzero) digits is 32, while the sum is 13.

Adding to 1202210020201 its reverse (1020200122021), we get a palindrome (2222410142222).

The spelling of 1202210020201 in words is "one trillion, two hundred two billion, two hundred ten million, twenty thousand, two hundred one".

Divisors: 1 212987 5644523 1202210020201