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1202210223113 is a prime number
BaseRepresentation
bin10001011111101001010…
…100000011010000001001
311020221010002122002002202
4101133221110003100021
5124144111304114423
62320142053205545
7152566614201134
oct21375124032011
94227102562082
101202210223113
11423944369469
12174bb59308b5
13894a2488633
1442289ca721b
1521413c76728
hex117e9503409

1202210223113 has 2 divisors, whose sum is σ = 1202210223114. Its totient is φ = 1202210223112.

The previous prime is 1202210223101. The next prime is 1202210223127. The reversal of 1202210223113 is 3113220122021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 794365777984 + 407844445129 = 891272^2 + 638627^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1202210223113 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1202210223713) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601105111556 + 601105111557.

It is an arithmetic number, because the mean of its divisors is an integer number (601105111557).

Almost surely, 21202210223113 is an apocalyptic number.

It is an amenable number.

1202210223113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202210223113 is an equidigital number, since it uses as much as digits as its factorization.

1202210223113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 1202210223113 its reverse (3113220122021), we get a palindrome (4315430345134).

The spelling of 1202210223113 in words is "one trillion, two hundred two billion, two hundred ten million, two hundred twenty-three thousand, one hundred thirteen".