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12022120000 = 26541189307
BaseRepresentation
bin10110011001001001…
…01111111001000000
31011000211201222021201
423030210233321000
5144110130320000
65304535430544
7603630222352
oct131444577100
934024658251
1012022120000
11510a19a770
1223b6225454
13119790ab97
148209390d2
154a568e96a
hex2cc92fe40

12022120000 has 280 divisors, whose sum is σ = 32993563680. Its totient is φ = 4308480000.

The previous prime is 12022119953. The next prime is 12022120049. The reversal of 12022120000 is 2122021.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 39159847 + ... + 39160153.

It is an arithmetic number, because the mean of its divisors is an integer number (117834156).

Almost surely, 212022120000 is an apocalyptic number.

12022120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12022120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16496781840).

12022120000 is an abundant number, since it is smaller than the sum of its proper divisors (20971443680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12022120000 is an equidigital number, since it uses as much as digits as its factorization.

12022120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 439 (or 414 counting only the distinct ones).

The product of its (nonzero) digits is 16, while the sum is 10.

Adding to 12022120000 its reverse (2122021), we get a palindrome (12024242021).

The spelling of 12022120000 in words is "twelve billion, twenty-two million, one hundred twenty thousand".