Base | Representation |
---|---|
bin | 10001011111101001011… |
… | …011100110001011010011 |
3 | 11020221010020100120111011 |
4 | 101133221123212023103 |
5 | 124144112310414141 |
6 | 2320142203431351 |
7 | 152566640050102 |
oct | 21375133461323 |
9 | 4227106316434 |
10 | 1202212201171 |
11 | 42394549a623 |
12 | 174bb6525557 |
13 | 894a29cba97 |
14 | 4228a260039 |
15 | 21414017881 |
hex | 117e96e62d3 |
1202212201171 has 2 divisors, whose sum is σ = 1202212201172. Its totient is φ = 1202212201170.
The previous prime is 1202212201153. The next prime is 1202212201181. The reversal of 1202212201171 is 1711022122021.
It is a strong prime.
It is an emirp because it is prime and its reverse (1711022122021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1202212201171 - 25 = 1202212201139 is a prime.
It is not a weakly prime, because it can be changed into another prime (1202212201181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601106100585 + 601106100586.
It is an arithmetic number, because the mean of its divisors is an integer number (601106100586).
Almost surely, 21202212201171 is an apocalyptic number.
1202212201171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1202212201171 is an equidigital number, since it uses as much as digits as its factorization.
1202212201171 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 22.
Adding to 1202212201171 its reverse (1711022122021), we get a palindrome (2913234323192).
The spelling of 1202212201171 in words is "one trillion, two hundred two billion, two hundred twelve million, two hundred one thousand, one hundred seventy-one".
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