120221222100101 has 4 divisors (see below), whose sum is σ = 120700191112704. Its totient is φ = 119742253087500.

The previous prime is 120221222100047. The next prime is 120221222100131. The reversal of 120221222100101 is 101001222122021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120221222100101 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 120221222100101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120221222100131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 239484505925 + ... + 239484506426.

It is an arithmetic number, because the mean of its divisors is an integer number (30175047778176).

Almost surely, 2^{120221222100101} is an apocalyptic number.

It is an amenable number.

120221222100101 is a deficient number, since it is larger than the sum of its proper divisors (478969012603).

120221222100101 is an equidigital number, since it uses as much as digits as its factorization.

120221222100101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 478969012602.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 120221222100101 its reverse (101001222122021), we get a palindrome (221222444222122).

The spelling of 120221222100101 in words is "one hundred twenty trillion, two hundred twenty-one billion, two hundred twenty-two million, one hundred thousand, one hundred one".