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1202213001000 = 233531172750111
BaseRepresentation
bin10001011111101001011…
…110101001011100101000
311020221010021212012122110
4101133221132221130220
5124144113012013000
62320142232522320
7152566646621004
oct21375136513450
94227107765573
101202213001000
11423945996540
12174bb68503a0
13894a2c1bb5b
144228a3cb704
1521414124850
hex117e97a9728

1202213001000 has 256 divisors, whose sum is σ = 4097606123520. Its totient is φ = 291038880000.

The previous prime is 1202213000993. The next prime is 1202213001023. The reversal of 1202213001000 is 1003122021.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 23965945 + ... + 24016055.

It is an arithmetic number, because the mean of its divisors is an integer number (16006273920).

Almost surely, 21202213001000 is an apocalyptic number.

1202213001000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1202213001000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2048803061760).

1202213001000 is an abundant number, since it is smaller than the sum of its proper divisors (2895393122520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1202213001000 is a wasteful number, since it uses less digits than its factorization.

1202213001000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50873 (or 50859 counting only the distinct ones).

The product of its (nonzero) digits is 24, while the sum is 12.

Adding to 1202213001000 its reverse (1003122021), we get a palindrome (1203216123021).

The spelling of 1202213001000 in words is "one trillion, two hundred two billion, two hundred thirteen million, one thousand".