Base | Representation |
---|---|
bin | 11011010101011100111100… |
… | …111010001011101010000001 |
3 | 120202200001120122210011122012 |
4 | 123111130330322023222001 |
5 | 111224202013033424033 |
6 | 1103404550010222305 |
7 | 34215466432456343 |
oct | 3325347472135201 |
9 | 522601518704565 |
10 | 120221451467393 |
11 | 353406a4206361 |
12 | 11597880a24995 |
13 | 5210aaca52503 |
14 | 2198a6c105293 |
15 | dd7380ea5248 |
hex | 6d573ce8ba81 |
120221451467393 has 2 divisors, whose sum is σ = 120221451467394. Its totient is φ = 120221451467392.
The previous prime is 120221451467309. The next prime is 120221451467401. The reversal of 120221451467393 is 393764154122021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 112857647408704 + 7363804058689 = 10623448^2 + 2713633^2 .
It is a cyclic number.
It is not a de Polignac number, because 120221451467393 - 246 = 49852707289729 is a prime.
It is not a weakly prime, because it can be changed into another prime (120221451461393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60110725733696 + 60110725733697.
It is an arithmetic number, because the mean of its divisors is an integer number (60110725733697).
Almost surely, 2120221451467393 is an apocalyptic number.
It is an amenable number.
120221451467393 is a deficient number, since it is larger than the sum of its proper divisors (1).
120221451467393 is an equidigital number, since it uses as much as digits as its factorization.
120221451467393 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2177280, while the sum is 50.
The spelling of 120221451467393 in words is "one hundred twenty trillion, two hundred twenty-one billion, four hundred fifty-one million, four hundred sixty-seven thousand, three hundred ninety-three".
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