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120223110214 = 260111555107
BaseRepresentation
bin110111111110111011…
…0110001010001000110
3102111022112222210011201
41233331312301101012
53432204104011324
6131121342253114
711454145401334
oct1577566612106
9374275883151
10120223110214
1146a938a2129
121b37258719a
13b44c4a364c
145b66c22b54
1531d9877444
hex1bfddb1446

120223110214 has 4 divisors (see below), whose sum is σ = 180334665324. Its totient is φ = 60111555106.

The previous prime is 120223110211. The next prime is 120223110251. The reversal of 120223110214 is 412011322021.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1202231102142 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120223110191 and 120223110200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (120223110211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30055777552 + ... + 30055777555.

It is an arithmetic number, because the mean of its divisors is an integer number (45083666331).

Almost surely, 2120223110214 is an apocalyptic number.

120223110214 is a deficient number, since it is larger than the sum of its proper divisors (60111555110).

120223110214 is an equidigital number, since it uses as much as digits as its factorization.

120223110214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60111555109.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 120223110214 its reverse (412011322021), we get a palindrome (532234432235).

The spelling of 120223110214 in words is "one hundred twenty billion, two hundred twenty-three million, one hundred ten thousand, two hundred fourteen".

Divisors: 1 2 60111555107 120223110214