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120223225445633 is a prime number
BaseRepresentation
bin11011010101011110100110…
…101001010111110100000001
3120202200020011021211121021222
4123111132212221113310001
5111224214131203230013
61103405442020524425
734215561413154512
oct3325364651276401
9522606137747258
10120223225445633
1135341424607482
1211598096b50715
13521100343128b
142198b99966a09
15dd7436abd508
hex6d57a6a57d01

120223225445633 has 2 divisors, whose sum is σ = 120223225445634. Its totient is φ = 120223225445632.

The previous prime is 120223225445497. The next prime is 120223225445639. The reversal of 120223225445633 is 336544522322021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 118592274240064 + 1630951205569 = 10890008^2 + 1277087^2 .

It is a cyclic number.

It is not a de Polignac number, because 120223225445633 - 214 = 120223225429249 is a prime.

It is not a weakly prime, because it can be changed into another prime (120223225445639) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60111612722816 + 60111612722817.

It is an arithmetic number, because the mean of its divisors is an integer number (60111612722817).

Almost surely, 2120223225445633 is an apocalyptic number.

It is an amenable number.

120223225445633 is a deficient number, since it is larger than the sum of its proper divisors (1).

120223225445633 is an equidigital number, since it uses as much as digits as its factorization.

120223225445633 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2073600, while the sum is 44.

Adding to 120223225445633 its reverse (336544522322021), we get a palindrome (456767747767654).

The spelling of 120223225445633 in words is "one hundred twenty trillion, two hundred twenty-three billion, two hundred twenty-five million, four hundred forty-five thousand, six hundred thirty-three".