12022333113333 has 4 divisors (see below), whose sum is σ = 16029777484448. Its totient is φ = 8014888742220.

The previous prime is 12022333113311. The next prime is 12022333113389. The reversal of 12022333113333 is 33331133322021.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 12022333113333 - 2¹⁶ = 12022333047797 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 12022333113333.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12022333111333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2003722185553 + ... + 2003722185558.

It is an arithmetic number, because the mean of its divisors is an integer number (4007444371112).

Almost surely, 2^{12022333113333} is an apocalyptic number.

It is an amenable number.

12022333113333 is a deficient number, since it is larger than the sum of its proper divisors (4007444371115).

12022333113333 is an equidigital number, since it uses as much as digits as its factorization.

12022333113333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4007444371114.

The product of its (nonzero) digits is 17496, while the sum is 30.

Adding to 12022333113333 its reverse (33331133322021), we get a palindrome (45353466435354).

The spelling of 12022333113333 in words is "twelve trillion, twenty-two billion, three hundred thirty-three million, one hundred thirteen thousand, three hundred thirty-three".