Base | Representation |
---|---|
bin | 11011010101100110000010… |
… | …101100000110000001010011 |
3 | 120202200222202220011101122012 |
4 | 123111212002230012001103 |
5 | 111224332010300122003 |
6 | 1103413242322533135 |
7 | 34216263342551114 |
oct | 3325460254060123 |
9 | 522628686141565 |
10 | 120231212114003 |
11 | 353448528a9651 |
12 | 115997458071ab |
13 | 52119a6c87253 |
14 | 219931656020b |
15 | dd7752d338d8 |
hex | 6d5982b06053 |
120231212114003 has 2 divisors, whose sum is σ = 120231212114004. Its totient is φ = 120231212114002.
The previous prime is 120231212113997. The next prime is 120231212114059. The reversal of 120231212114003 is 300411212132021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 120231212114003 - 218 = 120231211851859 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 120231212114003.
It is not a weakly prime, because it can be changed into another prime (120231212114903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60115606057001 + 60115606057002.
It is an arithmetic number, because the mean of its divisors is an integer number (60115606057002).
Almost surely, 2120231212114003 is an apocalyptic number.
120231212114003 is a deficient number, since it is larger than the sum of its proper divisors (1).
120231212114003 is an equidigital number, since it uses as much as digits as its factorization.
120231212114003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 120231212114003 its reverse (300411212132021), we get a palindrome (420642424246024).
The spelling of 120231212114003 in words is "one hundred twenty trillion, two hundred thirty-one billion, two hundred twelve million, one hundred fourteen thousand, three".
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