Base | Representation |
---|---|
bin | 1010111011110110011010… |
… | …0000000001011101110011 |
3 | 1120120102022202111000202222 |
4 | 2232331212200001131303 |
5 | 3033442241240212042 |
6 | 41323235404031255 |
7 | 2350441255243601 |
oct | 256754640013563 |
9 | 46512282430688 |
10 | 12023333132147 |
11 | 3916081118397 |
12 | 1422251b3252b |
13 | 692a457aa35c |
14 | 2d7d0a826871 |
15 | 15cb4b5d62d2 |
hex | aef66801773 |
12023333132147 has 2 divisors, whose sum is σ = 12023333132148. Its totient is φ = 12023333132146.
The previous prime is 12023333132131. The next prime is 12023333132197. The reversal of 12023333132147 is 74123133332021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12023333132147 - 24 = 12023333132131 is a prime.
It is not a weakly prime, because it can be changed into another prime (12023333132197) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6011666566073 + 6011666566074.
It is an arithmetic number, because the mean of its divisors is an integer number (6011666566074).
Almost surely, 212023333132147 is an apocalyptic number.
12023333132147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12023333132147 is an equidigital number, since it uses as much as digits as its factorization.
12023333132147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 35.
Adding to 12023333132147 its reverse (74123133332021), we get a palindrome (86146466464168).
The spelling of 12023333132147 in words is "twelve trillion, twenty-three billion, three hundred thirty-three million, one hundred thirty-two thousand, one hundred forty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •