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120234129978433 is a prime number
BaseRepresentation
bin11011010101101000110000…
…100110110111010001000001
3120202201021022020122021011011
4123111220300212313101001
5111224403444233302213
61103414444034520521
734216425553154362
oct3325506046672101
9522637266567134
10120234129978433
113534600a96a359
121159a21aa36141
135212050641353
142199511ca5b69
15dd78740a103d
hex6d5a309b7441

120234129978433 has 2 divisors, whose sum is σ = 120234129978434. Its totient is φ = 120234129978432.

The previous prime is 120234129978419. The next prime is 120234129978449. The reversal of 120234129978433 is 334879921432021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65903417720464 + 54330712257969 = 8118092^2 + 7370937^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120234129978433 is a prime.

It is not a weakly prime, because it can be changed into another prime (120234129988433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60117064989216 + 60117064989217.

It is an arithmetic number, because the mean of its divisors is an integer number (60117064989217).

Almost surely, 2120234129978433 is an apocalyptic number.

It is an amenable number.

120234129978433 is a deficient number, since it is larger than the sum of its proper divisors (1).

120234129978433 is an equidigital number, since it uses as much as digits as its factorization.

120234129978433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15676416, while the sum is 58.

The spelling of 120234129978433 in words is "one hundred twenty trillion, two hundred thirty-four billion, one hundred twenty-nine million, nine hundred seventy-eight thousand, four hundred thirty-three".