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1202343102041 is a prime number
BaseRepresentation
bin10001011111110001001…
…110111100011001011001
311020221110100200000201112
4101133301032330121121
5124144344313231131
62320203201230105
7152603116512224
oct21376116743131
94227410600645
101202343102041
11423a02377364
12175032332335
13894c3b71613
144229d7b65bb
152142077302b
hex117f13bc659

1202343102041 has 2 divisors, whose sum is σ = 1202343102042. Its totient is φ = 1202343102040.

The previous prime is 1202343102019. The next prime is 1202343102061. The reversal of 1202343102041 is 1402013432021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 971082139225 + 231260962816 = 985435^2 + 480896^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1202343102041 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1202343101998 and 1202343102016.

It is not a weakly prime, because it can be changed into another prime (1202343102061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601171551020 + 601171551021.

It is an arithmetic number, because the mean of its divisors is an integer number (601171551021).

Almost surely, 21202343102041 is an apocalyptic number.

It is an amenable number.

1202343102041 is a deficient number, since it is larger than the sum of its proper divisors (1).

1202343102041 is an equidigital number, since it uses as much as digits as its factorization.

1202343102041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 1202343102041 its reverse (1402013432021), we get a palindrome (2604356534062).

The spelling of 1202343102041 in words is "one trillion, two hundred two billion, three hundred forty-three million, one hundred two thousand, forty-one".