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12024445553 is a prime number
BaseRepresentation
bin10110011001011011…
…00111101001110001
31011001000010010100022
423030231213221301
5144111224224203
65305101333225
7603656046401
oct131455475161
934030103308
1012024445553
115110538a0a
1223b6b67215
131198243553
14820d82801
154a599da38
hex2ccb67a71

12024445553 has 2 divisors, whose sum is σ = 12024445554. Its totient is φ = 12024445552.

The previous prime is 12024445513. The next prime is 12024445613. The reversal of 12024445553 is 35554442021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11443008784 + 581436769 = 106972^2 + 24113^2 .

It is a cyclic number.

It is not a de Polignac number, because 12024445553 - 210 = 12024444529 is a prime.

It is a super-2 number, since 2×120244455532 (a number of 21 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (12024445513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6012222776 + 6012222777.

It is an arithmetic number, because the mean of its divisors is an integer number (6012222777).

Almost surely, 212024445553 is an apocalyptic number.

It is an amenable number.

12024445553 is a deficient number, since it is larger than the sum of its proper divisors (1).

12024445553 is an equidigital number, since it uses as much as digits as its factorization.

12024445553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96000, while the sum is 35.

Adding to 12024445553 its reverse (35554442021), we get a palindrome (47578887574).

The spelling of 12024445553 in words is "twelve billion, twenty-four million, four hundred forty-five thousand, five hundred fifty-three".