Base | Representation |
---|---|
bin | 10110011001100010… |
… | …10011101100000001 |
3 | 1011001001221020112201 |
4 | 23030301103230001 |
5 | 144112001143403 |
6 | 5305134153201 |
7 | 604000214143 |
oct | 131461235401 |
9 | 34031836481 |
10 | 12025412353 |
11 | 5111039319 |
12 | 23b7352801 |
13 | 11984c1616 |
14 | 821154c93 |
15 | 4a5ae021d |
hex | 2ccc53b01 |
12025412353 has 2 divisors, whose sum is σ = 12025412354. Its totient is φ = 12025412352.
The previous prime is 12025412279. The next prime is 12025412401. The reversal of 12025412353 is 35321452021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10909384704 + 1116027649 = 104448^2 + 33407^2 .
It is a cyclic number.
It is not a de Polignac number, because 12025412353 - 221 = 12023315201 is a prime.
It is a super-2 number, since 2×120254123532 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12025412953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6012706176 + 6012706177.
It is an arithmetic number, because the mean of its divisors is an integer number (6012706177).
Almost surely, 212025412353 is an apocalyptic number.
It is an amenable number.
12025412353 is a deficient number, since it is larger than the sum of its proper divisors (1).
12025412353 is an equidigital number, since it uses as much as digits as its factorization.
12025412353 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 12025412353 its reverse (35321452021), we get a palindrome (47346864374).
The spelling of 12025412353 in words is "twelve billion, twenty-five million, four hundred twelve thousand, three hundred fifty-three".
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