Base | Representation |
---|---|
bin | 111000000001100001… |
… | …0101110100110101001 |
3 | 102111112121201220101222 |
4 | 1300003002232212221 |
5 | 3432343343143423 |
6 | 131134131351425 |
7 | 11456253145514 |
oct | 1600302564651 |
9 | 374477656358 |
10 | 120310131113 |
11 | 47028a29227 |
12 | 1b397752575 |
13 | b4645215c3 |
14 | 5b745d5d7b |
15 | 31e23163c8 |
hex | 1c030ae9a9 |
120310131113 has 2 divisors, whose sum is σ = 120310131114. Its totient is φ = 120310131112.
The previous prime is 120310131107. The next prime is 120310131127. The reversal of 120310131113 is 311131013021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 91595811904 + 28714319209 = 302648^2 + 169453^2 .
It is a cyclic number.
It is not a de Polignac number, because 120310131113 - 212 = 120310127017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 120310131091 and 120310131100.
It is not a weakly prime, because it can be changed into another prime (120310131313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60155065556 + 60155065557.
It is an arithmetic number, because the mean of its divisors is an integer number (60155065557).
Almost surely, 2120310131113 is an apocalyptic number.
It is an amenable number.
120310131113 is a deficient number, since it is larger than the sum of its proper divisors (1).
120310131113 is an equidigital number, since it uses as much as digits as its factorization.
120310131113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 120310131113 its reverse (311131013021), we get a palindrome (431441144134).
The spelling of 120310131113 in words is "one hundred twenty billion, three hundred ten million, one hundred thirty-one thousand, one hundred thirteen".
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