Base | Representation |
---|---|
bin | 10001100000100000001… |
… | …101010111110010010001 |
3 | 11021000111021122112001211 |
4 | 101200200031113302101 |
5 | 124203003043002324 |
6 | 2320413313300121 |
7 | 152631466424452 |
oct | 21404015276221 |
9 | 4230437575054 |
10 | 1203131219089 |
11 | 424277231368 |
12 | 175212264641 |
13 | 895bb223877 |
14 | 4233632b129 |
15 | 21469a4e294 |
hex | 11820357c91 |
1203131219089 has 2 divisors, whose sum is σ = 1203131219090. Its totient is φ = 1203131219088.
The previous prime is 1203131219063. The next prime is 1203131219153. The reversal of 1203131219089 is 9809121313021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1172005438464 + 31125780625 = 1082592^2 + 176425^2 .
It is an emirp because it is prime and its reverse (9809121313021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1203131219089 - 25 = 1203131219057 is a prime.
It is not a weakly prime, because it can be changed into another prime (1273131219089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 601565609544 + 601565609545.
It is an arithmetic number, because the mean of its divisors is an integer number (601565609545).
Almost surely, 21203131219089 is an apocalyptic number.
It is an amenable number.
1203131219089 is a deficient number, since it is larger than the sum of its proper divisors (1).
1203131219089 is an equidigital number, since it uses as much as digits as its factorization.
1203131219089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 40.
The spelling of 1203131219089 in words is "one trillion, two hundred three billion, one hundred thirty-one million, two hundred nineteen thousand, eighty-nine".
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