Base | Representation |
---|---|
bin | 1010111100010100001010… |
… | …0011100011110011011010 |
3 | 1120121011221101012200000112 |
4 | 2233011002203203303122 |
5 | 3034110120410422132 |
6 | 41331040114404322 |
7 | 2351143216516550 |
oct | 257050243436332 |
9 | 46534841180015 |
10 | 12031320014042 |
11 | 39194aa545a2a |
12 | 14239008906a2 |
13 | 6937193a9584 |
14 | 2d8467477bd0 |
15 | 15ce6788eab2 |
hex | af1428e3cda |
12031320014042 has 32 divisors (see below), whose sum is σ = 20733882384384. Its totient is φ = 5129091442800.
The previous prime is 12031320014041. The next prime is 12031320014093. The reversal of 12031320014042 is 24041002313021.
12031320014042 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×120313200140422 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12031320013999 and 12031320014017.
It is not an unprimeable number, because it can be changed into a prime (12031320014041) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 88717067 + ... + 88852577.
It is an arithmetic number, because the mean of its divisors is an integer number (647933824512).
Almost surely, 212031320014042 is an apocalyptic number.
12031320014042 is a deficient number, since it is larger than the sum of its proper divisors (8702562370342).
12031320014042 is a wasteful number, since it uses less digits than its factorization.
12031320014042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 168914.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 12031320014042 its reverse (24041002313021), we get a palindrome (36072322327063).
The spelling of 12031320014042 in words is "twelve trillion, thirty-one billion, three hundred twenty million, fourteen thousand, forty-two".
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