12031401281 has 2 divisors, whose sum is σ = 12031401282. Its totient is φ = 12031401280.

The previous prime is 12031401233. The next prime is 12031401359. The reversal of 12031401281 is 18210413021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11752511281 + 278890000 = 108409^2 + 16700^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12031401281 is a prime.

It is a super-2 number, since 2×12031401281² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12031401181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6015700640 + 6015700641.

It is an arithmetic number, because the mean of its divisors is an integer number (6015700641).

Almost surely, 2^12031401281 is an apocalyptic number.

It is an amenable number.

12031401281 is a deficient number, since it is larger than the sum of its proper divisors (1).

12031401281 is an equidigital number, since it uses as much as digits as its factorization.

12031401281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 23.

The spelling of 12031401281 in words is "twelve billion, thirty-one million, four hundred one thousand, two hundred eighty-one".