Search a number
-
+
120315254401 is a prime number
BaseRepresentation
bin111000000001101011…
…0010001011010000001
3102111112222101012020101
41300003112101122001
53432401201120101
6131134433242401
711456344534306
oct1600326213201
9374488335211
10120315254401
1147030908451
121b399403401
13b4655c6534
145b7516b0ad
1531e29c9401
hex1c03591681

120315254401 has 2 divisors, whose sum is σ = 120315254402. Its totient is φ = 120315254400.

The previous prime is 120315254387. The next prime is 120315254407. The reversal of 120315254401 is 104452513021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109412762176 + 10902492225 = 330776^2 + 104415^2 .

It is an emirp because it is prime and its reverse (104452513021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120315254401 - 29 = 120315253889 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 120315254401.

It is not a weakly prime, because it can be changed into another prime (120315254407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60157627200 + 60157627201.

It is an arithmetic number, because the mean of its divisors is an integer number (60157627201).

Almost surely, 2120315254401 is an apocalyptic number.

It is an amenable number.

120315254401 is a deficient number, since it is larger than the sum of its proper divisors (1).

120315254401 is an equidigital number, since it uses as much as digits as its factorization.

120315254401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4800, while the sum is 28.

Adding to 120315254401 its reverse (104452513021), we get a palindrome (224767767422).

The spelling of 120315254401 in words is "one hundred twenty billion, three hundred fifteen million, two hundred fifty-four thousand, four hundred one".