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12032000100499 is a prime number
BaseRepresentation
bin1010111100010110101100…
…0101111000100010010011
31120121020200202220122020211
42233011223011320202103
53034113014011203444
641331231411144551
72351166115252111
oct257055305704223
946536622818224
1012032000100499
113919819423a55
121423a705a5157
136937c72659b2
142d84cd90aab1
1515cea742bc34
hexaf16b178893

12032000100499 has 2 divisors, whose sum is σ = 12032000100500. Its totient is φ = 12032000100498.

The previous prime is 12032000100391. The next prime is 12032000100509. The reversal of 12032000100499 is 99400100023021.

12032000100499 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12032000100499 is a prime.

It is a super-2 number, since 2×120320001004992 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12032000100499.

It is not a weakly prime, because it can be changed into another prime (12032000200499) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6016000050249 + 6016000050250.

It is an arithmetic number, because the mean of its divisors is an integer number (6016000050250).

Almost surely, 212032000100499 is an apocalyptic number.

12032000100499 is a deficient number, since it is larger than the sum of its proper divisors (1).

12032000100499 is an equidigital number, since it uses as much as digits as its factorization.

12032000100499 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 12032000100499 in words is "twelve trillion, thirty-two billion, one hundred thousand, four hundred ninety-nine".