Base | Representation |
---|---|
bin | 1010111100011010100111… |
… | …1100001011100000000001 |
3 | 1120121100102020222202201202 |
4 | 2233012221330023200001 |
5 | 3034122143424140340 |
6 | 41331524155110545 |
7 | 2351234210552264 |
oct | 257065174134001 |
9 | 46540366882652 |
10 | 12033054521345 |
11 | 391a20a637a40 |
12 | 1424105742455 |
13 | 693934848560 |
14 | 2d858d982cdb |
15 | 15d019cacc15 |
hex | af1a9f0b801 |
12033054521345 has 32 divisors (see below), whose sum is σ = 16974260553600. Its totient is φ = 8073287792640.
The previous prime is 12033054521317. The next prime is 12033054521353. The reversal of 12033054521345 is 54312545033021.
It is not a de Polignac number, because 12033054521345 - 216 = 12033054455809 is a prime.
It is a super-2 number, since 2×120330545213452 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12033054521299 and 12033054521308.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3855920 + ... + 6239729.
It is an arithmetic number, because the mean of its divisors is an integer number (530445642300).
Almost surely, 212033054521345 is an apocalyptic number.
It is an amenable number.
12033054521345 is a deficient number, since it is larger than the sum of its proper divisors (4941206032255).
12033054521345 is a wasteful number, since it uses less digits than its factorization.
12033054521345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10097345.
The product of its (nonzero) digits is 216000, while the sum is 38.
Adding to 12033054521345 its reverse (54312545033021), we get a palindrome (66345599554366).
The spelling of 12033054521345 in words is "twelve trillion, thirty-three billion, fifty-four million, five hundred twenty-one thousand, three hundred forty-five".
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