Base | Representation |
---|---|
bin | 11011010111000011000110… |
… | …010000100101001101001011 |
3 | 120210001112200100021220221001 |
4 | 123113003012100211031023 |
5 | 111233001123240001303 |
6 | 1103531205153555431 |
7 | 34226431401560563 |
oct | 3327030620451513 |
9 | 523045610256831 |
10 | 120331130000203 |
11 | 3538316694a401 |
12 | 115b4b8bb75b77 |
13 | 521b23b776435 |
14 | 21a00b4727da3 |
15 | dda14ec4d31d |
hex | 6d70c642534b |
120331130000203 has 2 divisors, whose sum is σ = 120331130000204. Its totient is φ = 120331130000202.
The previous prime is 120331130000177. The next prime is 120331130000219. The reversal of 120331130000203 is 302000031133021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120331130000203 is a prime.
It is not a weakly prime, because it can be changed into another prime (120331130000273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60165565000101 + 60165565000102.
It is an arithmetic number, because the mean of its divisors is an integer number (60165565000102).
Almost surely, 2120331130000203 is an apocalyptic number.
120331130000203 is a deficient number, since it is larger than the sum of its proper divisors (1).
120331130000203 is an equidigital number, since it uses as much as digits as its factorization.
120331130000203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 120331130000203 its reverse (302000031133021), we get a palindrome (422331161133224).
The spelling of 120331130000203 in words is "one hundred twenty trillion, three hundred thirty-one billion, one hundred thirty million, two hundred three", and thus it is an aban number.
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