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12034333025881 is a prime number
BaseRepresentation
bin1010111100011111011000…
…1001010010011001011001
31120121110201100201112020121
42233013312021102121121
53034132303223312011
641332255105553241
72351310663634615
oct257076611223131
946543640645217
1012034333025881
11391a806293361
121424401945821
13693aa969850a
142d86716aa345
1515d092153e71
hexaf1f6252659

12034333025881 has 2 divisors, whose sum is σ = 12034333025882. Its totient is φ = 12034333025880.

The previous prime is 12034333025843. The next prime is 12034333025899. The reversal of 12034333025881 is 18852033343021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12018979585600 + 15353440281 = 3466840^2 + 123909^2 .

It is a cyclic number.

It is not a de Polignac number, because 12034333025881 - 29 = 12034333025369 is a prime.

It is a super-2 number, since 2×120343330258812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12034333025831) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6017166512940 + 6017166512941.

It is an arithmetic number, because the mean of its divisors is an integer number (6017166512941).

Almost surely, 212034333025881 is an apocalyptic number.

It is an amenable number.

12034333025881 is a deficient number, since it is larger than the sum of its proper divisors (1).

12034333025881 is an equidigital number, since it uses as much as digits as its factorization.

12034333025881 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 414720, while the sum is 43.

The spelling of 12034333025881 in words is "twelve trillion, thirty-four billion, three hundred thirty-three million, twenty-five thousand, eight hundred eighty-one".