Base | Representation |
---|---|
bin | 1010111100100110111101… |
… | …0111010010101001010011 |
3 | 1120121122222002111220121122 |
4 | 2233021233113102221103 |
5 | 3034200434341140201 |
6 | 41333232555312455 |
7 | 2351412250134503 |
oct | 257115727225123 |
9 | 46548862456548 |
10 | 12036366740051 |
11 | 392065a267975 |
12 | 142488aa4b72b |
13 | 694041b18294 |
14 | 2d87c581da03 |
15 | 15d160975e1b |
hex | af26f5d2a53 |
12036366740051 has 2 divisors, whose sum is σ = 12036366740052. Its totient is φ = 12036366740050.
The previous prime is 12036366739921. The next prime is 12036366740119. The reversal of 12036366740051 is 15004766363021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12036366740051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12036366739984 and 12036366740011.
It is not a weakly prime, because it can be changed into another prime (12036366700051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6018183370025 + 6018183370026.
It is an arithmetic number, because the mean of its divisors is an integer number (6018183370026).
Almost surely, 212036366740051 is an apocalyptic number.
12036366740051 is a deficient number, since it is larger than the sum of its proper divisors (1).
12036366740051 is an equidigital number, since it uses as much as digits as its factorization.
12036366740051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 544320, while the sum is 44.
The spelling of 12036366740051 in words is "twelve trillion, thirty-six billion, three hundred sixty-six million, seven hundred forty thousand, fifty-one".
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