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120383113 is a prime number
BaseRepresentation
bin1110010110011…
…10011010001001
322101112002120211
413023032122021
5221304224423
615540121121
72661145114
oct713163211
9271462524
10120383113
1161a53684
12343961a1
131bc2c416
1411db957b
15a87e10d
hex72ce689

120383113 has 2 divisors, whose sum is σ = 120383114. Its totient is φ = 120383112.

The previous prime is 120383099. The next prime is 120383129. The reversal of 120383113 is 311383021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 64850809 + 55532304 = 8053^2 + 7452^2 .

It is an emirp because it is prime and its reverse (311383021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 120383113 - 221 = 118285961 is a prime.

It is not a weakly prime, because it can be changed into another prime (120383143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60191556 + 60191557.

It is an arithmetic number, because the mean of its divisors is an integer number (60191557).

Almost surely, 2120383113 is an apocalyptic number.

It is an amenable number.

120383113 is a deficient number, since it is larger than the sum of its proper divisors (1).

120383113 is an equidigital number, since it uses as much as digits as its factorization.

120383113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 22.

The square root of 120383113 is about 10971.9238513581. The cubic root of 120383113 is about 493.7667671922.

It can be divided in two parts, 12038 and 3113, that added together give a palindrome (15151).

The spelling of 120383113 in words is "one hundred twenty million, three hundred eighty-three thousand, one hundred thirteen".