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12039488348113 is a prime number
BaseRepresentation
bin1010111100110010100101…
…1011010001111111010001
31120121222000122101000212001
42233030221123101333101
53034223333004114423
641334510430234001
72351552513306602
oct257145133217721
946558018330761
1012039488348113
113921a11338246
121425400355901
1369441b76a645
142d8a0023dda9
1515d294a3bcad
hexaf3296d1fd1

12039488348113 has 2 divisors, whose sum is σ = 12039488348114. Its totient is φ = 12039488348112.

The previous prime is 12039488348071. The next prime is 12039488348161. The reversal of 12039488348113 is 31184388493021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8413845839569 + 3625642508544 = 2900663^2 + 1904112^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12039488348113 is a prime.

It is not a weakly prime, because it can be changed into another prime (12039488348413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6019744174056 + 6019744174057.

It is an arithmetic number, because the mean of its divisors is an integer number (6019744174057).

Almost surely, 212039488348113 is an apocalyptic number.

It is an amenable number.

12039488348113 is a deficient number, since it is larger than the sum of its proper divisors (1).

12039488348113 is an equidigital number, since it uses as much as digits as its factorization.

12039488348113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3981312, while the sum is 55.

The spelling of 12039488348113 in words is "twelve trillion, thirty-nine billion, four hundred eighty-eight million, three hundred forty-eight thousand, one hundred thirteen".