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1204013212019 is a prime number
BaseRepresentation
bin10001100001010100110…
…001111010000101110011
311021002202202021101220122
4101201110301322011303
5124211304340241034
62321041021400455
7152662366304432
oct21412461720563
94232682241818
101204013212019
1142468a084742
1217541970912b
13896cbb83c87
14423bb51b119
15214bc1c062e
hex11854c7a173

1204013212019 has 2 divisors, whose sum is σ = 1204013212020. Its totient is φ = 1204013212018.

The previous prime is 1204013211997. The next prime is 1204013212027. The reversal of 1204013212019 is 9102123104021.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1204013212019 is a prime.

It is a super-2 number, since 2×12040132120192 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1204013212069) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602006606009 + 602006606010.

It is an arithmetic number, because the mean of its divisors is an integer number (602006606010).

Almost surely, 21204013212019 is an apocalyptic number.

1204013212019 is a deficient number, since it is larger than the sum of its proper divisors (1).

1204013212019 is an equidigital number, since it uses as much as digits as its factorization.

1204013212019 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864, while the sum is 26.

The spelling of 1204013212019 in words is "one trillion, two hundred four billion, thirteen million, two hundred twelve thousand, nineteen".