1204021324231 has 4 divisors (see below), whose sum is σ = 1313477808264. Its totient is φ = 1094564840200.

The previous prime is 1204021324217. The next prime is 1204021324237. The reversal of 1204021324231 is 1324231204021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1204021324231 - 2⁹ = 1204021323719 is a prime.

It is a super-2 number, since 2×1204021324231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1204021324196 and 1204021324205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1204021324237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54728242000 + ... + 54728242021.

It is an arithmetic number, because the mean of its divisors is an integer number (328369452066).

Almost surely, 2^{1204021324231} is an apocalyptic number.

1204021324231 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

1204021324231 is a deficient number, since it is larger than the sum of its proper divisors (109456484033).

1204021324231 is a wasteful number, since it uses less digits than its factorization.

1204021324231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 109456484032.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1204021324231 its reverse (1324231204021), we get a palindrome (2528252528252).

The spelling of 1204021324231 in words is "one trillion, two hundred four billion, twenty-one million, three hundred twenty-four thousand, two hundred thirty-one".