Base | Representation |
---|---|
bin | 10001100001011000001… |
… | …101000110000001100001 |
3 | 11021002220202101121001001 |
4 | 101201120031012001201 |
5 | 124211414042423213 |
6 | 2321050433112001 |
7 | 152663664554611 |
oct | 21413015060141 |
9 | 4232822347031 |
10 | 1204070670433 |
11 | 42470955a034 |
12 | 1754349b8601 |
13 | 8970aa51137 |
14 | 423c4dd6a41 |
15 | 214c22701dd |
hex | 11858346061 |
1204070670433 has 2 divisors, whose sum is σ = 1204070670434. Its totient is φ = 1204070670432.
The previous prime is 1204070670419. The next prime is 1204070670463. The reversal of 1204070670433 is 3340760704021.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1177251040144 + 26819630289 = 1085012^2 + 163767^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1204070670433 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1204070670392 and 1204070670401.
It is not a weakly prime, because it can be changed into another prime (1204070670463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602035335216 + 602035335217.
It is an arithmetic number, because the mean of its divisors is an integer number (602035335217).
Almost surely, 21204070670433 is an apocalyptic number.
It is an amenable number.
1204070670433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1204070670433 is an equidigital number, since it uses as much as digits as its factorization.
1204070670433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84672, while the sum is 37.
The spelling of 1204070670433 in words is "one trillion, two hundred four billion, seventy million, six hundred seventy thousand, four hundred thirty-three".
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