Base | Representation |
---|---|
bin | 10110011011011100… |
… | …00010110100100011 |
3 | 1011002011220011000020 |
4 | 23031232002310203 |
5 | 144130040142201 |
6 | 5310503324523 |
7 | 604252436115 |
oct | 131556026443 |
9 | 34064804006 |
10 | 12041334051 |
11 | 511a02354a |
12 | 2400750743 |
13 | 119b8a7646 |
14 | 8232db3b5 |
15 | 4a71d7a36 |
hex | 2cdb82d23 |
12041334051 has 8 divisors (see below), whose sum is σ = 16147916880. Its totient is φ = 7981153632.
The previous prime is 12041334043. The next prime is 12041334091. The reversal of 12041334051 is 15043314021.
It is a happy number.
12041334051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 12041334051 - 23 = 12041334043 is a prime.
It is not an unprimeable number, because it can be changed into a prime (12041334091) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11599996 + ... + 11601033.
It is an arithmetic number, because the mean of its divisors is an integer number (2018489610).
Almost surely, 212041334051 is an apocalyptic number.
12041334051 is a deficient number, since it is larger than the sum of its proper divisors (4106582829).
12041334051 is a wasteful number, since it uses less digits than its factorization.
12041334051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 23201205.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 12041334051 its reverse (15043314021), we get a palindrome (27084648072).
The spelling of 12041334051 in words is "twelve billion, forty-one million, three hundred thirty-four thousand, fifty-one".
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