Base | Representation |
---|---|
bin | 10001100001011100010… |
… | …000100110000000101111 |
3 | 11021010002111101200121022 |
4 | 101201130100212000233 |
5 | 124212034001244001 |
6 | 2321101303124355 |
7 | 152665452021224 |
oct | 21413420460057 |
9 | 4233074350538 |
10 | 1204138696751 |
11 | 4247439a2231 |
12 | 1754537436bb |
13 | 8971bb7b4b3 |
14 | 423d006394b |
15 | 214c820b11b |
hex | 1185c42602f |
1204138696751 has 4 divisors (see below), whose sum is σ = 1204175696712. Its totient is φ = 1204101696792.
The previous prime is 1204138696741. The next prime is 1204138696753. The reversal of 1204138696751 is 1576968314021.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1204138696751 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1204138696693 and 1204138696702.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1204138696753) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18451121 + ... + 18516266.
It is an arithmetic number, because the mean of its divisors is an integer number (301043924178).
It is a 1-persistent number, because it is pandigital, but 2⋅1204138696751 = 2408277393502 is not.
Almost surely, 21204138696751 is an apocalyptic number.
1204138696751 is a deficient number, since it is larger than the sum of its proper divisors (36999961).
1204138696751 is an equidigital number, since it uses as much as digits as its factorization.
1204138696751 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 36999960.
The product of its (nonzero) digits is 2177280, while the sum is 53.
The spelling of 1204138696751 in words is "one trillion, two hundred four billion, one hundred thirty-eight million, six hundred ninety-six thousand, seven hundred fifty-one".
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