Base | Representation |
---|---|
bin | 10110011011011100… |
… | …11001001011100001 |
3 | 1011002012001210122011 |
4 | 23031232121023201 |
5 | 144130101110013 |
6 | 5310505312521 |
7 | 604253300116 |
oct | 131556311341 |
9 | 34065053564 |
10 | 12041425633 |
11 | 511a086336 |
12 | 2400795741 |
13 | 119b90a233 |
14 | 82332290d |
15 | 4a7204c3d |
hex | 2cdb992e1 |
12041425633 has 2 divisors, whose sum is σ = 12041425634. Its totient is φ = 12041425632.
The previous prime is 12041425621. The next prime is 12041425637. The reversal of 12041425633 is 33652414021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7209368464 + 4832057169 = 84908^2 + 69513^2 .
It is an emirp because it is prime and its reverse (33652414021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12041425633 - 233 = 3451491041 is a prime.
It is a super-3 number, since 3×120414256333 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12041425595 and 12041425604.
It is not a weakly prime, because it can be changed into another prime (12041425637) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6020712816 + 6020712817.
It is an arithmetic number, because the mean of its divisors is an integer number (6020712817).
Almost surely, 212041425633 is an apocalyptic number.
It is an amenable number.
12041425633 is a deficient number, since it is larger than the sum of its proper divisors (1).
12041425633 is an equidigital number, since it uses as much as digits as its factorization.
12041425633 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 12041425633 its reverse (33652414021), we get a palindrome (45693839654).
The spelling of 12041425633 in words is "twelve billion, forty-one million, four hundred twenty-five thousand, six hundred thirty-three".
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