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12043141143 = 311364943671
BaseRepresentation
bin10110011011101001…
…11100000000010111
31011002022021221212120
423031310330000113
5144131021004033
65311010151023
7604304003445
oct131564740027
934068257776
1012043141143
115120048210
122401282473
13119c08b027
1482364bb95
154a74431b3
hex2cdd3c017

12043141143 has 8 divisors (see below), whose sum is σ = 17517296256. Its totient is φ = 7298873400.

The previous prime is 12043141087. The next prime is 12043141153. The reversal of 12043141143 is 34114134021.

12043141143 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12043141143 - 212 = 12043137047 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12043141153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 182471803 + ... + 182471868.

It is an arithmetic number, because the mean of its divisors is an integer number (2189662032).

Almost surely, 212043141143 is an apocalyptic number.

12043141143 is a deficient number, since it is larger than the sum of its proper divisors (5474155113).

12043141143 is a wasteful number, since it uses less digits than its factorization.

12043141143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 364943685.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 12043141143 its reverse (34114134021), we get a palindrome (46157275164).

The spelling of 12043141143 in words is "twelve billion, forty-three million, one hundred forty-one thousand, one hundred forty-three".

Divisors: 1 3 11 33 364943671 1094831013 4014380381 12043141143