12043304431 has 8 divisors (see below), whose sum is σ = 12081484800. Its totient is φ = 12005150520.

The previous prime is 12043304423. The next prime is 12043304437. The reversal of 12043304431 is 13440334021.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 12043304431 - 2³ = 12043304423 is a prime.

It is a super-2 number, since 2×12043304431² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12043304396 and 12043304405.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12043304437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1298910 + ... + 1308148.

It is an arithmetic number, because the mean of its divisors is an integer number (1510185600).

Almost surely, 2^12043304431 is an apocalyptic number.

12043304431 is a deficient number, since it is larger than the sum of its proper divisors (38180369).

12043304431 is an equidigital number, since it uses as much as digits as its factorization.

12043304431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13229.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 12043304431 its reverse (13440334021), we get a palindrome (25483638452).

The spelling of 12043304431 in words is "twelve billion, forty-three million, three hundred four thousand, four hundred thirty-one".