Base | Representation |
---|---|
bin | 11011011000100010000100… |
… | …011101111110011110000101 |
3 | 120210102021220012001111222022 |
4 | 123120202010131332132011 |
5 | 111241133444442233110 |
6 | 1104050112125212525 |
7 | 34240001423460035 |
oct | 3330420435763605 |
9 | 523367805044868 |
10 | 120433105430405 |
11 | 35412436370449 |
12 | 116108ab401145 |
13 | 5227a40609a91 |
14 | 21a4dc9c898c5 |
15 | ddcb1c5e5755 |
hex | 6d888477e785 |
120433105430405 has 24 divisors (see below), whose sum is σ = 152957097588096. Its totient is φ = 90859513273760.
The previous prime is 120433105430387. The next prime is 120433105430411. The reversal of 120433105430405 is 504034501334021.
It is not a de Polignac number, because 120433105430405 - 28 = 120433105430149 is a prime.
It is a super-3 number, since 3×1204331054304053 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 103292969 + ... + 104452398.
It is an arithmetic number, because the mean of its divisors is an integer number (6373212399504).
Almost surely, 2120433105430405 is an apocalyptic number.
It is an amenable number.
120433105430405 is a deficient number, since it is larger than the sum of its proper divisors (32523992157691).
120433105430405 is an equidigital number, since it uses as much as digits as its factorization.
120433105430405 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 207745537 (or 207745466 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 120433105430405 its reverse (504034501334021), we get a palindrome (624467606764426).
The spelling of 120433105430405 in words is "one hundred twenty trillion, four hundred thirty-three billion, one hundred five million, four hundred thirty thousand, four hundred five".
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