Base | Representation |
---|---|
bin | 111000000101001011… |
… | …1110111100000101110 |
3 | 102111212012011001000122 |
4 | 1300022113313200232 |
5 | 3433121334110014 |
6 | 131154243324542 |
7 | 11462305366625 |
oct | 1601227674056 |
9 | 374765131018 |
10 | 120433113134 |
11 | 47091397464 |
12 | 1b410980752 |
13 | b483b50929 |
14 | 5b86a8a6bc |
15 | 31ed00a58e |
hex | 1c0a5f782e |
120433113134 has 4 divisors (see below), whose sum is σ = 180649669704. Its totient is φ = 60216556566.
The previous prime is 120433113131. The next prime is 120433113137. The reversal of 120433113134 is 431311334021.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 431311334021 = 631171 ⋅683351.
It is an interprime number because it is at equal distance from previous prime (120433113131) and next prime (120433113137).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120433113131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30108278282 + ... + 30108278285.
It is an arithmetic number, because the mean of its divisors is an integer number (45162417426).
Almost surely, 2120433113134 is an apocalyptic number.
120433113134 is a deficient number, since it is larger than the sum of its proper divisors (60216556570).
120433113134 is an equidigital number, since it uses as much as digits as its factorization.
120433113134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 60216556569.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 120433113134 its reverse (431311334021), we get a palindrome (551744447155).
The spelling of 120433113134 in words is "one hundred twenty billion, four hundred thirty-three million, one hundred thirteen thousand, one hundred thirty-four".
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