Base | Representation |
---|---|
bin | 11011011000100010010000… |
… | …010000111010110010000101 |
3 | 120210102022101222110001200212 |
4 | 123120202100100322302011 |
5 | 111241134401123142041 |
6 | 1104050143515045205 |
7 | 34240006345563356 |
oct | 3330422020726205 |
9 | 523368358401625 |
10 | 120433303334021 |
11 | 35412528051357 |
12 | 11610945740805 |
13 | 5227a7260bb02 |
14 | 21a5008283d2d |
15 | ddcb2eb888eb |
hex | 6d889043ac85 |
120433303334021 has 8 divisors (see below), whose sum is σ = 120606989983704. Its totient is φ = 120259739392000.
The previous prime is 120433303333927. The next prime is 120433303334107.
120433303334021 is nontrivially palindromic in base 10.
It can be written as a sum of positive squares in 4 ways, for example, as 7463742040225 + 112969561293796 = 2731985^2 + 10628714^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120433303334021 is a prime.
It is a super-3 number, since 3×1204333033340213 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120433303334621) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28712480 + ... + 32638521.
It is an arithmetic number, because the mean of its divisors is an integer number (15075873747963).
Almost surely, 2120433303334021 is an apocalyptic number.
It is an amenable number.
120433303334021 is a deficient number, since it is larger than the sum of its proper divisors (173686649683).
120433303334021 is a wasteful number, since it uses less digits than its factorization.
120433303334021 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61353831.
The product of its (nonzero) digits is 46656, while the sum is 32.
It can be divided in two parts, 12043330 and 3334021, that added together give a palindrome (15377351).
The spelling of 120433303334021 in words is "one hundred twenty trillion, four hundred thirty-three billion, three hundred three million, three hundred thirty-four thousand, twenty-one".
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