Base | Representation |
---|---|
bin | 10001100001101100000… |
… | …101101011010000110011 |
3 | 11021010210000010012210102 |
4 | 101201230011223100303 |
5 | 124213104443121011 |
6 | 2321143511223015 |
7 | 153005155244516 |
oct | 21415405532063 |
9 | 4233700105712 |
10 | 1204404270131 |
11 | 42486a8a2467 |
12 | 175508677a6b |
13 | 89761bb44ca |
14 | 42417434d7d |
15 | 214e16b973b |
hex | 1186c16b433 |
1204404270131 has 2 divisors, whose sum is σ = 1204404270132. Its totient is φ = 1204404270130.
The previous prime is 1204404270071. The next prime is 1204404270149. The reversal of 1204404270131 is 1310724044021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1204404270131 is a prime.
It is a super-2 number, since 2×12044042701312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1204404270094 and 1204404270103.
It is not a weakly prime, because it can be changed into another prime (1204404270191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 602202135065 + 602202135066.
It is an arithmetic number, because the mean of its divisors is an integer number (602202135066).
Almost surely, 21204404270131 is an apocalyptic number.
1204404270131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1204404270131 is an equidigital number, since it uses as much as digits as its factorization.
1204404270131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 29.
The spelling of 1204404270131 in words is "one trillion, two hundred four billion, four hundred four million, two hundred seventy thousand, one hundred thirty-one".
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