Base | Representation |
---|---|
bin | 11011011000101100100000… |
… | …100000010011101111110101 |
3 | 120210110100211021111022212122 |
4 | 123120230200200103233311 |
5 | 111241324423141102013 |
6 | 1104055204215125325 |
7 | 34240546235231465 |
oct | 3330544040235765 |
9 | 523410737438778 |
10 | 120444313222133 |
11 | 3541716792323a |
12 | 11612ab8973845 |
13 | 5228b085b90c4 |
14 | 21a57705a9ba5 |
15 | ddd07652ca08 |
hex | 6d8b20813bf5 |
120444313222133 has 4 divisors (see below), whose sum is σ = 120444416947020. Its totient is φ = 120444209497248.
The previous prime is 120444313222127. The next prime is 120444313222153. The reversal of 120444313222133 is 331222313444021.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 96066226590244 + 24378086631889 = 9801338^2 + 4937417^2 .
It is a cyclic number.
It is not a de Polignac number, because 120444313222133 - 242 = 116046266711029 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 120444313222093 and 120444313222102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120444313222153) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50100710 + ... + 52449687.
It is an arithmetic number, because the mean of its divisors is an integer number (30111104236755).
Almost surely, 2120444313222133 is an apocalyptic number.
It is an amenable number.
120444313222133 is a deficient number, since it is larger than the sum of its proper divisors (103724887).
120444313222133 is a wasteful number, since it uses less digits than its factorization.
120444313222133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 103724886.
The product of its (nonzero) digits is 82944, while the sum is 35.
Adding to 120444313222133 its reverse (331222313444021), we get a palindrome (451666626666154).
The spelling of 120444313222133 in words is "one hundred twenty trillion, four hundred forty-four billion, three hundred thirteen million, two hundred twenty-two thousand, one hundred thirty-three".
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