12045041530231 has 4 divisors (see below), whose sum is σ = 12070187755200. Its totient is φ = 12019895305264.

The previous prime is 12045041530139. The next prime is 12045041530267. The reversal of 12045041530231 is 13203514054021.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12045041530231 - 2⁷ = 12045041530103 is a prime.

It is a super-2 number, since 2×12045041530231² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12045041530193 and 12045041530202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12045041534231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12573111766 + ... + 12573112723.

It is an arithmetic number, because the mean of its divisors is an integer number (3017546938800).

Almost surely, 2^{12045041530231} is an apocalyptic number.

12045041530231 is a deficient number, since it is larger than the sum of its proper divisors (25146224969).

12045041530231 is an equidigital number, since it uses as much as digits as its factorization.

12045041530231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25146224968.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 12045041530231 its reverse (13203514054021), we get a palindrome (25248555584252).

The spelling of 12045041530231 in words is "twelve trillion, forty-five billion, forty-one million, five hundred thirty thousand, two hundred thirty-one".