Base | Representation |
---|---|
bin | 1010111101000111010001… |
… | …1010111111010110011011 |
3 | 1120122111100122122220200011 |
4 | 2233101310122333112123 |
5 | 3034321221112432032 |
6 | 41341225442222351 |
7 | 2352140233501204 |
oct | 257216432772633 |
9 | 46574318586604 |
10 | 12045041530267 |
11 | 3924300a26189 |
12 | 14264b00549b7 |
13 | 694ac50b1c45 |
14 | 2d8da997c5ab |
15 | 15d4bc314247 |
hex | af4746bf59b |
12045041530267 has 2 divisors, whose sum is σ = 12045041530268. Its totient is φ = 12045041530266.
The previous prime is 12045041530139. The next prime is 12045041530303. The reversal of 12045041530267 is 76203514054021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12045041530267 - 27 = 12045041530139 is a prime.
It is not a weakly prime, because it can be changed into another prime (12045041530867) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6022520765133 + 6022520765134.
It is an arithmetic number, because the mean of its divisors is an integer number (6022520765134).
Almost surely, 212045041530267 is an apocalyptic number.
12045041530267 is a deficient number, since it is larger than the sum of its proper divisors (1).
12045041530267 is an equidigital number, since it uses as much as digits as its factorization.
12045041530267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 201600, while the sum is 40.
Adding to 12045041530267 its reverse (76203514054021), we get a palindrome (88248555584288).
The spelling of 12045041530267 in words is "twelve trillion, forty-five billion, forty-one million, five hundred thirty thousand, two hundred sixty-seven".
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