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12045052524643 is a prime number
BaseRepresentation
bin1010111101000111010100…
…0100111011100001100011
31120122111101102100111010021
42233101311010323201203
53034321231421242033
641341230514014311
72352140426111605
oct257216504734143
946574342314107
1012045052524643
113924307155446
1214264b3877397
13694ac74612a8
142d8dab201175
1515d4bd286b2d
hexaf47513b863

12045052524643 has 2 divisors, whose sum is σ = 12045052524644. Its totient is φ = 12045052524642.

The previous prime is 12045052524629. The next prime is 12045052524653. The reversal of 12045052524643 is 34642525054021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 12045052524643 - 225 = 12045018970211 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12045052524643.

It is not a weakly prime, because it can be changed into another prime (12045052524653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6022526262321 + 6022526262322.

It is an arithmetic number, because the mean of its divisors is an integer number (6022526262322).

Almost surely, 212045052524643 is an apocalyptic number.

12045052524643 is a deficient number, since it is larger than the sum of its proper divisors (1).

12045052524643 is an equidigital number, since it uses as much as digits as its factorization.

12045052524643 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152000, while the sum is 43.

Adding to 12045052524643 its reverse (34642525054021), we get a palindrome (46687577578664).

The spelling of 12045052524643 in words is "twelve trillion, forty-five billion, fifty-two million, five hundred twenty-four thousand, six hundred forty-three".